Seven eighths cooling time–
Produce temperature after 6 h–
Average refrigeration load while cooling–
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Newton cooling in halves

Produce cools roughly like any warm object in colder air: the rate is proportional to the temperature gap. That gives exponential cooling, T = room + (start minus room) x 0.5 raised to (time / half cooling time). After three half cooling times, seven eighths of the gap is gone.

The room is held at 2 °C in this model. Real half cooling times depend on package vents, stacking, and airflow, and are measured rather than calculated.

Try it: with 4,000 kg at 30 °C, set the half cooling time to 1 hour. The produce reaches about 2.4 °C in 6 hours but the refrigeration load jumps past 35 kW. Slide it to 6 hours and the load falls under 9 kW while the produce is still near 16 °C.

The load, simplified

Field heat is mass x specific heat x temperature drop; the model uses 3.9 kJ/kg·°C and averages that heat over the seven eighths cooling time. It adds respiration at a flat 0.1 W/kg and wall gains of 0.3 W/m²·°C over 180 m² with 30 °C outside. These are teaching assumptions; real respiration rates vary several fold between crops.

How to cite this model

Avid Solutions International. (2026, November 11). How a cold room pulls heat out of produce [Interactive 3D model]. Avid Field Lab. https://avidsolutionsintl.com/explore/cold-storage-room

Last updated November 11, 2026

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